At What temperature will a solution freeze if 200 grams of calcium chloride, CaCl2, is dissolved in 850 mL of water? kf H2O = 1.86°C/m
∆T = KF·m
Molar mass of CaCl2 = 110.98 g/mol
200/110.98= 1.8mol
850/1000= 0.85kg
= 1.86× 0.85× 1.8= 2.8°C
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