Answer to Question #250763 in General Chemistry for Indecisive

Question

How many grams of silver chloride will be precipitated by adding sufficient silver nitrate to react with 1500.mL of 0.400M barium chloride solution?

Answer 1

To calculate the moles, we use the equation:

According to stoichiometry:

1 mole of BaCl2 produce = 2 moles of AgCl

Thus 0.6 moles BaCl2 will produce

1.2moles of AgCl

Mass

Thus 172.2 g of AgCl is formed by adding sufficient silver nitrate to react with 1500.0mL of 0.400M barium