Answer to Question #250514 in General Chemistry for Loom

Question #250514

31.5 g NH4Cl is dissolved in 500.ml H2O initially at 23c . Determine the final temperature of the resulting solution

Expert's answer

V2=0.5l*T2-23/10

V2=31.5/53.5*22.4=13.19l

13.2*10/0.5=T2-23

T2-23=264

T2=287

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