Answer to Question #250337 in General Chemistry for Liezel

General Chemistry

Question #250337

What volume of 0.250 M solution can be prepared from 16.0 g of potassium carbonate?

Expert's answer

Moles of potassium carbonate "=\\frac{16}{138.205}=0.116moles"

Volume "=\\frac{0.116}{0.250}=0.464l"

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