Question

What is the limiting and excess reactant in the reaction between 3 moles of NH3 and 6 moles of Cuo?

Step 1 Balance the equation

Step 2. Using the ratio and propotion method, calculate the amount of CuO needed to react with moles of NH, based on the balance equation.

Answer 1

$2NH_3+3CuO\to N_2+3Cu+3H_2O$

given 3 moles of $NH_3$ and 6 moles of CuO

$NH_3: 3mol/2(coefficient)=1.5$

CuO: 6mol$/3=2$

limiting reactant is $NH_3$ and excess reactant is CuO.

moles of CuO required =(1.5 moles of $NH_3 \times$ 3 moles CuO)$/$ (2 moles $NH_3$ )=2.25moles