Question

The typical starting reaction mixture has 3:1 mole ratio of NH3 to CO2. If 44.7g urea forms per mole of CO2 that reacts, what is the theoretical yield, actual yield, and percent yield?

Answer 1

Molar mass of urea = 60.06 g/mol

Moles of urea $=\frac{44.7}{60.06}=$0.744

Moles of NH3$=0.744×3=2.23moles$

Mass of $NH_3= 2.33×17.031=38.03grams$