Methanol, CH3OH, is produced in the reaction: CO2 + 2H2 → CH3OH. How many moles of methanol can be produced when 4.5 mol of CO reacts with 7.2 mol H2?
Solution.
First you need to determine which substance is in excess.
"n(CO2) = \\frac{4.5}{1} = 4.5 \\ mol"
"n(H2) = \\frac{7.2}{2} = 3.6 \\ mol"
Thus, CO2 is in excess. Therefore
"n(CH3OH) = \\frac{n(H2)}{2} = \\frac{7.2}{2} = 3.6 \\ mol"
Answer:
n(CH3OH) = 3.6 mol
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