What volume will 10 L of gas at 450 torr occupy if the pressure is increased to 910 torr at constant temperature
V1=10 LP1=450 torrV2= ?P2=910 torrV_1 = 10\textsf{ L}\\ P_1= 450\textsf{ torr}\\ V_2=\ ?\\ P_2 = 910\textsf{ torr}V1=10 LP1=450 torrV2= ?P2=910 torr
According to Boyle's law;
P1V1=P2V2450×10=910×V2V2=4.95 LP_1V_1 = P_2V_2\\ 450×10 = 910× V_2\\ V_2 = 4.95\textsf{ L}P1V1=P2V2450×10=910×V2V2=4.95 L
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments