Answer to Question #248954 in General Chemistry for Seph

Question #248954

Use the following reactions to find ∆H when 1 mol of HCl gas forms from its elements:

N2(g) + 3H2(g) → 2NH3(g) ∆H= -91.8 kJ
N2(g) + 4H2(g) + Cl2(g) → 2NH4Cl(s) ∆H= -628.8 kJ
NH3(g) + HCl(g) → NH4Cl(s) ∆H= -176.2 kJ

Expert's answer

"-176.2-628.8-91.8=-896.8kJ"

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