Question

Use the following reactions to find ∆H when 1 mol of HCl gas forms from its elements:

N2(g) + 3H2(g) → 2NH3(g) ∆H= -91.8 kJ
N2(g) + 4H2(g) + Cl2(g) → 2NH4Cl(s) ∆H= -628.8 kJ
NH3(g) + HCl(g) → NH4Cl(s) ∆H= -176.2 kJ

Answer 1

$-176.2-628.8-91.8=-896.8kJ$