Question #248750

How many grams of barium nitrate, Ba(NO3)2, must be dissolved to prepare 500. mL of a 0.169 M aqueous solution of the salt?



1
Expert's answer
2021-10-10T10:25:15-0400

Moles of Ba(NO3)2=0.169×5001000=0.098molesBa(NO_3)_2=0.169×\frac{500}{1000}=0.098moles


Molar mass of Ba(NO3)2=261.337g/molBa(NO_3)_2= 261.337 g/mol


Mass=261.337×0.098=25.611026grams=261.337×0.098=25.611026grams



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