Answer to Question #248750 in General Chemistry for gia

Question

How many grams of barium nitrate, Ba(NO₃)₂, must be dissolved to prepare 500. mL of a 0.169 M aqueous solution of the salt?

Answer 1

Moles of $Ba(NO_3)_2=0.169×\frac{500}{1000}=0.098moles$

Molar mass of $Ba(NO_3)_2= 261.337 g/mol$

Mass$=261.337×0.098=25.611026grams$