Answer to Question #248047 in General Chemistry for banihfrance05

Question

Find the molecular formula of nicotine given the empirical formula C5H7N wuth the molecular mass of 194.

Answer 1

$C_5H_7N \to 5\times 12+ 7\times 1 +14=81$

Molecular mass =194

$n=194/81=2.425=2$

molecular formula $=n \times$ empirical formula$=2\times C_5H_7N=C_{10}H_{14}N_2$