Answer to Question #247938 in General Chemistry for Vince Amoyo

Question

Calculate the number of grams of oxygen that would react with 0.125 g Fes

Answer 1

The balanced chemical equation will be

4FeS + 7O₂ --> 2Fe₂O₃ + 4SO₂

Amount of FeS given = 0.125g

Molecular Weight of FeS = 55+32 = 87

Moles of FeS = 0.125/87

Now as per the balanced equation, 4 Moles of FeS react with 7 Moles of O₂

Therefore, 0.125/87 moles of FeS will react with = (7/4)*(0.125/87) = 0.0025 moles of O₂

0.0025 = amount in gram / 32 => amount in gram = 0.0025*32 = 0.08g

So Amount of oxygen required is 0.08g