how many moles of HNO3 will be produced from the reaction of 63.5g of NO2 with excess water in the following chemical reaction 3NO2 + H2O -> 2HNO3 + NO
Molar mass of NO2= 46.0055 g/mol
= 63.5/46.0055= 1.38mol
Mole ratio of NO2: HNO3 = 3:2
= 2×1.38/3 = 0.92mol
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