Question

Determine the mass percent of iron in Fe4[Fe(CN)6]3

Answer 1

Fe₄[Fe₄(CN)₆ ]₃

Fe$\to$ 7

C$\to$ 18

N$\to$ 18

Molar mass of Fe[ Fe₄(CN)₆]₃

( 7× 55.845) +( 18 × 12.0107) +(18×14.0067)

= 859.2282

Mass of Fe = 7×55.845

= 390.915

Mass percentage of Fe = (390.915 / 859.2282) × 100

= 45.496 %