A gas is collected at 22.0 ˚C and 745.0 mm Hg. When the temperature is changed to 0 ˚C, what is the resulting pressure?
"T_1 = 22+273 =295 \\;K \\\\\n\nT_2 = 0 + 273 = 273 \\;K \\\\\n\np_1 = 745.0 \\;mmHg \\\\\n\n\\frac{p_1}{T_1} = \\frac{p_2}{T_2} \\\\\n\np_2 = \\frac{p_1T_2}{T_1} \\\\\n\n= \\frac{745.0 \\times 273}{295} = 689.44 \\;mmHg"
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