Determine the empirical formula of the compound containing 87.5% nitrogen and 12.5% H by mass
Let total mass be 100
Assuming 100g of compounds N would be 87.5g and 12.5g H, then amount of
N = 87.5/14 which is 6.25mol
H = 12.5/1 which is 12.5mol
"\\therefore" N : H =6.25:12.5
N : H = 1 : 2
The empirical formula for this compound is NH2
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