Answer to Question #247312 in General Chemistry for Noel Gonzalo Jr.

Question

The specific heat of aluminum is 0.902j/g.°C.How much heat is absorbed by an aluminum pie tin with a mass of 473g to raise its temperature from room temperature (23.00°C)to oven temperature(375°F

Answer 1

375oF =(375-32)*(5/9)oC

=190.5oC

Increase in temperature =190.5-23

=167.5

Required Heat= 0.902*167.5*473 J

=71463.205 J