Answer to Question #247170 in General Chemistry for Dollar

Question

It requires 15.6 mL of 0.100 M NaOH to neutralize 15.0 mL of H,SO ,.

What is the concentration of H,SO, solution?

Answer 1

2NaOH (aq) + H₂SO₄ (aq) $\to$ Na₂SO₄ (aq) + 2 H₂O (l)

Moles of NaOH= (15.6/1000)× 0.100

= 0.00156 moles

moles of H₂SO₄= ?

If 2 $\implies$ 0.00156 moles

$\because$ 1$\implies$ 1/2 × 0.00156

= 0.00078 moles

Molarity =( moles × 100) / volume

=( 0.00078× 1000 ) / 15.0

=0.052M