1. "Al(OH)_3 + 3HCl \\to AlCl_3 + 3H_2O"
2.
From the reaction above,
1 mole of "Al(OH)_3" neutralizes 3 moles of HCl
78g of "Al(OH)_3" neutralizes 109.5 moles og HCl
300mg of the"Al(OH)_3" neutralizes x mg of HCl
x = 300 × 109.5/78 = 421.15 mg
"\\therefore" 421.15mg of HCl can be neutralized by one tablespoon of the antacid.
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