Question

Calculate how many grams of O2(g)

can be produced from heating 35.7 g KClO3(s)

Answer 1

2KCLO3 -> 2KCL + 3O2

Moles of $KClO_3=\frac{35.7}{123}=0.29 moles$

$Moles$ of $O_2=\frac{3}{2}×0.29=0.435moles$

Mass of $O_2=0.435×32=13.92grams$