Answer to Question #246649 in General Chemistry for Nana

Question #246649

What is the pH of an aqueous solution of 0.006534 M Ba(OH)₂ at 25^oC? (Give your answer to two decimal places)

Expert's answer

[OH

−

]=0.006534×2=0.0131M

⇒pOH=−log(0.0131)=1.88

As we know that,

pH+pOH=14

∴pH=14−pOH=14−1.88=12.12

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