concentration 1is equal 3.975 m, concentration is equal 6.532, quantity 2 is equal to 4.937 kg solvet and the mixed solution is equal to 5.421, find the quantity 1 and its unit
M1V1 = M2V2
Molality = moles/Kg of solvent
5.421=4.937
x. =6.532
4.937x =5.421*6.532
4.937x =35.41
x =35.409/4.937
x=7.17
the quantity 1 =7.17 kg
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