The combustion of glucose (C6H12O6) occurs in the presence of oxygen, producing carbon dioxide and water.
The equation for combustion of glucose can be written as shown below;
C6_66 H12_{12}12 O6_66 + 6O2_22 = 6CO2_22 + 6H2_22 O so the mole ratio can be written as 1:6:6:6
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