what is the imperical formula of an oxide of chromium is made up of 5.20 g chromium and 5.60 g oxygen?
Moles of Chromium"=\\frac{5.20}{52}=0.1"
Moles of oxygen "=\\frac{5.60}{16}=0.35"
Mole ratio =(0.1÷0.1)=1 and
(0.35÷0.1)=3.5=4
"CrO_4"
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