Question

what is the imperical formula of an oxide of chromium is made up of 5.20 g chromium and 5.60 g oxygen?

Answer 1

Moles of Chromium$=\frac{5.20}{52}=0.1$

Moles of oxygen $=\frac{5.60}{16}=0.35$

Mole ratio =(0.1÷0.1)=1 and

(0.35÷0.1)=3.5=4

$CrO_4$