Answer to Question #246232 in General Chemistry for ash

Question #246232

A sample of gas expands and increases its volume by 2.5 L while pushing a piston against an external force of 2 kPa.

 

What is the work done by the expanding gas?


1
Expert's answer
2021-10-05T01:46:02-0400

Pressure,P=2KPa=2000Pa=2000atmPressure , P=2KPa=2000Pa=2000atm

change in volume, ΔV=2.5L\Delta V=2.5L

work done, W=PΔV=2000atm×2.5L=5000L.atm=5000L.atm1×101.3J1L.atm=506500JW=-P\Delta V=-2000atm\times 2.5L=-5000L.atm=\frac{-5000L. atm}{1}\times \frac{101.3J}{1L.atm}=-506500J


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