A sample of gas expands and increases its volume by 2.5 L while pushing a piston against an external force of 2 kPa.
What is the work done by the expanding gas?
Pressure,P=2KPa=2000Pa=2000atmPressure , P=2KPa=2000Pa=2000atmPressure,P=2KPa=2000Pa=2000atm
change in volume, ΔV=2.5L\Delta V=2.5LΔV=2.5L
work done, W=−PΔV=−2000atm×2.5L=−5000L.atm=−5000L.atm1×101.3J1L.atm=−506500JW=-P\Delta V=-2000atm\times 2.5L=-5000L.atm=\frac{-5000L. atm}{1}\times \frac{101.3J}{1L.atm}=-506500JW=−PΔV=−2000atm×2.5L=−5000L.atm=1−5000L.atm×1L.atm101.3J=−506500J
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