Question

How much calcium chloride (FW=111g/mol) in grams will be needed to produce 1.00 gram of CaCO₃ (FW=100g/mol) assuming Na₂CO₃ is in excess

Answer 1

Na₂CO₃ (aq) + CaCl₂ (aq) → 2 NaCl (aq) + CaCO₃ (s)

Moles of $CaCO_3=\frac{1.00}{100}=0.01 moles$

Moles of calcium chloride $= 0.01moles$

Mass of calcium chloride $=0.01×111=1.11grams$