Explain how to make one liter of a 1.25 molal sodium hydroxide solution
Mol = M * L = (1.25 M) (1.0L)1.25 mol NH4OH35.0 g NH4OH= 43.8g mol NH4OH
Dissolve 43.8g(1.25moles) of ammonium hydroxide in 1L H2O
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment