What is the mass fraction and volume fraction of an aqueous solution having 0.7304 Mol Fraction, 0.6268 Specific Gravity of solute and 42.00 Molar Weight of solute?
Molar mass of solvent = 42/ 0.6268
= 66.8789
Total mass= 66.8789 + 42
= 108.8789
Mass fraction= 42/108.8789
= 0.3857
Volume fraction = 0.3857/ 0.7304
=0.528
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