Question

When a gas is bubbled through water at 298K a very dilute solution of the gas is obtained. Henry's law of constant for the gas at 298K is 150K bar. If the gas excerts a partial pressure of 2 bar the no. Of millimoles of the gas dissolved in 1L of water is

Answer 1

Henry’s law:

$P =K_Hx_{gas} \\ 2 = 150 \times 10^3 \times x \\ x = \frac{2}{150 \times 10^3} = 0.0133 \times 10^{-3} \;moles \\ x = 0.0133 \;millimoles$