Question

how many moles of naAIO2 is produced if 126.4g of NaOH reacts completely

Answer 1

$2Al+2NaOH+2H2O→2NaAlO2+3H2$

$Molar Mass of 2NaAlO2=(2×23)+(2×27)+(2×48)$

$=196g/mol$

$Moles=Mass/Molar Mass$

$=126.4g/196g/mol$

$=0.748Mol NaAlO2$