Question

How many grams of aluminum oxide are produced according to the reaction below given that you start with 10.0 g of 8L and 19.0 g of O2 reaction : 4Al + 3O2 ——> 2Al2O3

Answer 1

The balanced reaction is written as:

4Al(s)+3O2(g)→2Al2O3(s)

Moles of $O_2=\frac{19}{32}=0.59moles$

Moles of $Al_2O=\frac{0.59×2}{3}=0.39moles$

Mass of $Al_2O=102×0.39=39.78grams$