How many grams of aluminum oxide are produced according to the reaction below given that you start with 10.0 g of 8L and 19.0 g of O2 reaction : 4Al + 3O2 ——> 2Al2O3
The balanced reaction is written as:
4Al(s)+3O2(g)→2Al2O3(s)
Moles of "O_2=\\frac{19}{32}=0.59moles"
Moles of "Al_2O=\\frac{0.59\u00d72}{3}=0.39moles"
Mass of "Al_2O=102\u00d70.39=39.78grams"
Comments
Leave a comment