What is the % by volume (v/v) of solution if 7.5 L HCl is added to 1900 mL of water?
We can use the volume of water and HCl solution expressed in liters to find the percentage in volume with respect to HCl:
%(v/v)=vHClvT×100%(v/v)=vHClvHCl+vwater×100%(v/v)=7.5 L(7.5+1.9) L×100%(v/v)=7.5 L9.4 L×100 ⟹ %(v/v)=79.787%≊79.8%\%(v/v)=\cfrac{v_{HCl}}{v_{T}} \times 100 \\ \%(v/v) =\cfrac{v_{HCl}}{v_{HCl}+v_{water}}\times 100 \\ \%(v/v)=\cfrac{7.5\,L}{(7.5+1.9)\,L}\times 100 \\ \%(v/v)=\cfrac{7.5\,\cancel{L}}{9.4\, \cancel{L} }\times 100 \\ \implies \%(v/v)=79.787\%\approxeq79.8\%%(v/v)=vTvHCl×100%(v/v)=vHCl+vwatervHCl×100%(v/v)=(7.5+1.9)L7.5L×100%(v/v)=9.4L7.5L×100⟹%(v/v)=79.787%≊79.8%
Reference
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