Question

What volume of 5 M NaOH is needed to create a 100 mL solution of 1 M NaOH?

Answer 1

Number of moles(n)=Molarity(M)xvolume(V) in litres

$M_1\times V_1= M_2\times V_2$

$M_1=initial \;Molarity= 5.0 \;M\\ V_1=initial\; volume = \;? \;mL\\ M_2= diluted \;Molarity = 1.00\; M\\ V_2= diluted \;volume = 100\; mL\\$

$M_1\times V_1= M_2\times V_2 \\ 5.0\times V_1=1.00\times 100\\ V_1=20 mL$