Number of moles(n)=Molarity(M)xvolume(V) in litres
"M_1\\times V_1= M_2\\times V_2"
"M_1=initial \\;Molarity= 5.0 \\;M\\\\\n\nV_1=initial\\; volume = \\;? \\;mL\\\\\n\nM_2= diluted \\;Molarity = 1.00\\; M\\\\\n\nV_2= diluted \\;volume = 100\\; mL\\\\"
"M_1\\times V_1= M_2\\times V_2 \\\\\n\n5.0\\times V_1=1.00\\times 100\\\\\n\n\n\n\nV_1=20 mL"
Comments
Leave a comment