a sample contains of 14.2g chlorine gas.What is the volume of chlorine gas at room temperature and pressure? [Relative atomic mass,Cl=35.5;Molar volume of gas=24dm3 mol-1 at room temperature and pressure
M(Cl2) = 71 g/mol
n(Cl2) =mM=14.271=0.2 mol= \frac{m}{M} = \frac{14.2}{71} = 0.2 \;mol=Mm=7114.2=0.2mol
V(Cl2) =24×0.2=4.8 dm3= 24 \times 0.2 = 4.8 \;dm^3=24×0.2=4.8dm3
Answer: 4.8 dm3
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