Determine the pH and pOH of 0.25 L of a solution that is 0.0181 M boric acid and 0.0391 M sodium borate; pKa for B(OH)3 = 9.0 at 25°C.
pH=pKa+log"\\frac{A-}{HA}"
pH=9.00+log"\\frac{0.04}{0.0215}" ]
pH = 9.27
pOH=14-pH
pOH=14-9.27=4.73
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