Question

Determine the pH and pOH of 0.25 L of a solution that is 0.0181 M  boric acid and 0.0391 M sodium borate; pK_a for B(OH)₃ = 9.0 at 25°C.

Answer 1

pH=pKa+log$\frac{A-}{HA}$

pH=9.00+log$\frac{0.04}{0.0215}$ ]

pH = 9.27

pOH=14-pH

pOH=14-9.27=4.73