Answer to Question #244665 in General Chemistry for Hey

Question

329.0 g of SO2 (g), 433.4 g of CaCO3 (s), and 105.0 g of O2 (g) react as follows:


2 SO2 (g) + 2 CaCO3 (s) + O2 (g) ---> 2 CaSO4 (s) + 2 CO2 (g)

What mass (in g) of CaSO4 (s) do we produce?

Answer 1

2 SO2 (g) + 2 CaCO3 (s) + O2 (g) ---> 2 CaSO4 (s) + 2 CO2 (g)

number of moles of $CaCO_3=\frac{mass\space of \space CaCO_3}{molar \space mass\space of \space CaCO_3}=\frac{443.4}{100}=4.434moles$

mole ratio $CaCO_3:CaSO_4=2:2=1:1$

Therefore, moles of $CaSO_4=4.434$

Mass of $CaSO_4=number \space of \space moles \space of \space CaSO_4 \times$ $molar\space mass \space of \space CaSO_4=4.434\times136=603.024g$