Question #244635

What is the energy of a photon (in joules) emitted during a transition from ni = (5.00x100) state to the nf = (2.00x100) state of the hydrogen atom?

1
Expert's answer
2021-10-07T03:45:10-0400

Rydberg formula, 1λ=RH(1/nf21/ni2)\frac{1}{\lambda}=R_H(1/n_f^2-1/n_i^2)

nf=2,ni=5n_f=2, n_i=5

RH=10973731.56816R_H=10973731.56816

Energy of a photon, E=hf=hc/λ=hc×RH(1/nf21/ni2)E=hf=hc/\lambda=hc\times R_H(1/n_f^2-1/n_i^2)

E=6.626×1034×3×108×10973731.56816(1/221/52)=4.581×1019JE=6.626\times 10^{-34}\times 3\times 10^8\times 10973731.56816(1/2^2-1/5^2)=4.581\times 10^{-19}J


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