What is the energy of a photon (in joules) emitted during a transition from ni = (5.00x100) state to the nf = (2.00x100) state of the hydrogen atom?
Rydberg formula, 1λ=RH(1/nf2−1/ni2)\frac{1}{\lambda}=R_H(1/n_f^2-1/n_i^2)λ1=RH(1/nf2−1/ni2)
nf=2,ni=5n_f=2, n_i=5nf=2,ni=5
RH=10973731.56816R_H=10973731.56816RH=10973731.56816
Energy of a photon, E=hf=hc/λ=hc×RH(1/nf2−1/ni2)E=hf=hc/\lambda=hc\times R_H(1/n_f^2-1/n_i^2)E=hf=hc/λ=hc×RH(1/nf2−1/ni2)
E=6.626×10−34×3×108×10973731.56816(1/22−1/52)=4.581×10−19JE=6.626\times 10^{-34}\times 3\times 10^8\times 10973731.56816(1/2^2-1/5^2)=4.581\times 10^{-19}JE=6.626×10−34×3×108×10973731.56816(1/22−1/52)=4.581×10−19J
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