A Carl Hayden chemistry student conducted an experiment using a crude soda can calorimeter containing 100 g of water. The student recorded an initial water temperature of 20 ˚C. After burning a 0.4 g sample of food under the can, the student observed a maximum temperature of 40 ˚C.
Determine the amount of energy transferred from the food sample to the water.
Given m = 100 g is the mass of water warmed up.
C = 4.18 J/g˚ , Heat capacity (C) of liquid water
change in temperature = final temperature - initial temperature
Find Q =?
Use Q=m x C x change in temperature
Plug in the values in the above equation and calculate
The amount of energy transferred from the food sample to the water=Q=MXCX∆T
M=100g,
C=4.18J/g
∆T=(40-20)=20
100x4.18x20=8360joules
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