If 108.5 moles of FeCl3 is combined with 76.8 moles of AgNo3, how many moles of Agcl is produced? With solution
3AgNO3 + 3FeCl3 = 3AgCl + 3Fe(NO3)
Mole ratio of FeCl3:AgCl = 1:1
Mole ratio of AgNO3:AgCl = 1:1
108.5+76.8 = 185.3moles
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