1.0 mole of a gas occupies a volume of 22.4 L gas at 0 ̊C and 1 atm.
What would be the volume of 7.5 mol of the gas at the same temperature
and pressure?
P1V1n1T1=P2V2n2T2\frac{P1V1}{n1T1}=\frac{P2V2}{n2T2}n1T1P1V1=n2T2P2V2
×122.4×1273=×1x×7.5273\frac{\times{1}{22.4}}{\times{1}{273}}=\frac{\times{1}{x}}{\times{7.5}{273}}×1273×122.4=×7.5273×1x
0.08=x2047.50.08= \frac{x}{2047.5}0.08=2047.5x
x=163.8Lx = 163.8 Lx=163.8L
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