Answer to Question #242701 in General Chemistry for Buzz

Question

Imagine two containers.

Container “A” holds N2 gas with a mass of 64.2g and is 2 times the volume of container “B” which holds argon (Ar) gas at the exact same temperature and pressure. What is the mass of the Ar (in g) within container “B”?

Answer 1

The amount of N2 gas in "A": n = (64.2g)/(28g/mol) = 2.2929 mol

The amount of argon in cantainer "B" is half the amount of N2 because its volume is half the volume of "A": n = 2.29mol/2 = 1.1464 mol

The mass of argon in "B": m = (1.1464 mol)*(40 g/mol) = 45.86 g