Fe2O3(s) + 2Al(s) → 2Fe(l) + Al2O3(s) ... balanced equation
Note the mole ratio of iron oxide Fe2O3(s) to iron (Fe) is 1 : 2. Use this and dimensional analysis...
76.73 g Fe x 1 mol Fe/55.85 g x 1 mol Fe2O3/2 mol Fe x 159.69 g Fe2O3/mol Fe2O3 = 109.7 g Fe2O3
Now note the mole ratio of Al to Fe is 2 : 2 or 1 : 1. Use dimensional analysis again...
76.72 g Fe x 1 mol Fe/55.85 g x 2 mol Al/2 mol Fe x 26.98 g Al/mol Al = 37.06 g of Al
Mole ratio of Al2O3 to Fe is 1 : 2.
76.75 g Fe x 1 mol Fe/55.85 g x 1 mol Al2O3/2 mol Fe x 101.96 g Al2O3/mol Al2O3 = 70.06 g Al2O3
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