Question

In order to determine Ccal for a brand new calorimeter, a test reaction that is known to release 6.0 kJ of heat is carried out. The reaction causes a temperature increase of 3.7^oC. What is the heat capacity of the calorimeter (in kJ/^oC)?

Answer 1

$q=c\times \Delta t$

$C=$ $q\over \Delta t$

$=$ $6.0kJ\over 3.7°C$ $=1.62kJ/°C$