Two q's to 0.
(10.0 Au)(0.129)(Tf-18.0°C) + (20.0g Fe)(0.444)(Tf-55.6°C)=0
(1.29Tf-23.22) + (8.88Tf-502.608) = 0
10.17Tf = 525.828
Temperature final = 51.70°C
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment