The resistance of 0.1 N solution of an electrolyte is 50 ohms. If the distance between the electrodes is 1.6cm and the area of cross-section is 2.45cm. Calculate the equivalent conductivity.
Equivalent conductivity=4.3Ω−1cm−2mol−14.3 \Omega^{-1}cm^{-2}mol^{-1}4.3Ω−1cm−2mol−1
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