Use the equation: PI3 + 3H2O → 3HI + H3PO3 to determine the number of grams of HI that will results from the reaction of 5.00 g of PI3, assuming complete reaction?
PI3 + 3 H2O → H3PO3 + 3 HI
150 grams of PI3 (MM=411.7 g/mol) is added to 250 milliliters og H2O (MM=18.01 g/mol),
Mole ratio = 1:3:1:3
(150)(3) = 450g of H2O
Therefore = 250/450= 0.56moles
Therefore H3PO3 = 1:3
( 0.56 moles/3) =0.1852moles
(0.1852)(81.99) =15.18grames
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