Question #241372

Hydrogen gas was cooled from 423 K to 323 K. Its new volume is 75 mL. What was its original volume? Assume that pressure remains constant. *



1
Expert's answer
2021-09-24T02:21:54-0400

V(1)/T(1)=V(2)/T(2)V_(1) /T_(1) = V_(2) / T_(2)


T1=423k

V1= ?

T2=323k

V2=75mL


V1= (423×75) /323


V1= 98.23mL




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