In a biochemical assay, a chemist needs to add 2.93 g of glucose to a reaction mixture. Calculate the volume in mL of a 1.35M glucose solution she should use for the addition.
Molar mass of glucose: 180.156 g/mol
Moles of glucose =2.93180.159=0.016moles=\frac{2.93}{180.159}=0.016 moles=180.1592.93=0.016moles
Volumes of glucose =0.0161.35=0.0119l=11.9ml=\frac{0.016}{1.35}=0.0119l= 11.9ml=1.350.016=0.0119l=11.9ml
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