Question

Calculate the energy required to heat 24g of ice at -20℃ to steam at 250℃. The

heat of fusion of ice is 334 J/g and the heat of vaporization of water is 40.7 kJ/mol. The

specific heat capacity of ice and steam are 2.03 J/g℃ and 2.01 J/g℃ respectively.

Answer 1

specific heat is Q = cm∆T

specific heat ice $= 24×20×2.03 =974.4$

Specific heat steam $= 24×250×2.01=12060$