Question

Calculate the grams of O 6.64 g Li3PO4

Answer 1

Since lithium orthophosphate contains 3 lithium ions, the amount of lithium ion substance will be equal to:

$n(Li3PO4) = \frac{6.64}{115.79} = 0.0573\ mole$

$n(Li^+) = n(Li3PO4) \times 3 = 0.172 \ mole$