Calculate the grams of O 6.64 g Li3PO4
Since lithium orthophosphate contains 3 lithium ions, the amount of lithium ion substance will be equal to:
"n(Li3PO4) = \\frac{6.64}{115.79} = 0.0573\\ mole"
"n(Li^+) = n(Li3PO4) \\times 3 = 0.172 \\ mole"
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